Tuesday, December 15, 2009

15 December 2009

I took another stab at trying to detect the perturbation of Earth’s orbit due to its revolution about the Earth/Moon barycenter. I thought that if the Earth goes into retrograde motion once a month it should show up in the position of the sun along the ecliptic. I reasoned that the distance the Sun “moves” along the ecliptic should be lesser on those days and should show up in a plot of the Sun’s location as a string of data points that are closer together and that this should repeat at the same time during each lumation. I plotted the Sun’s azimuth at noon on each day of lunations 1077 and 1078 (15Jan10-15Mar10).

From the plot it is evident that all I am plotting is the motion of the sun along the analemma. The plot gets a bit jagged as it reaches the western elongation (west of 175°) but I think this is probably due to the precision with which Catres du Ciel (my data source) displays the Sun’s location. The Sun covers more distance (178.6° to 177°) during lunation 1077 than it does during lunation 1078 (177° to 178.3°) but this is due to the fact that during lunation 1077 it is trying to get to western elongation and during lunation 1078 it is spending time there then trying to get away.

Analemma.exe graphic

I am confident that if the data were plotted for the rest of the year the line would curve right to eastern elongation then bend back to the west.

Any variation in the Earth’s orbit due to its revolution around the Earth/Moon barycenter is too subtle for me to illustrate with the tools at my disposal. This must be due to the closeness or the relative barycenter to the Earth’s center.


While I was gathering my data in Cartes du Ciel I found that on 14Feb10 the Moon, Venus, and Jupiter will be in a tight cluster (within a ~6° circle) just east of the Sun (~7°), Neptune will be in conjunction with the Sun, and Mercury will not be too far off to the west (~20°). Uranus is also on that side of the sky ~29° east of the Sun. So all of those bodies will be within ~49° of each other.

Cartes du Ciel graphic

Then on 10Mar10 Venus and Uranus will be to the east of the Sun (14° and ~6° respectively), Mercury and Jupiter will be closer out to the west (~4° and ~8° respectively), and Neptune ~23° west making all of these bodies within ~37° of each other.

Assuming a Ptolemaic view of the Solar System,

that puts a lot of mass in one section of the celestial sphere.

 14Feb1010Mar10
 
Meridian graphic
Meridian graphic
Gathered
 Mass x1012 kgMass x1012 kg
Sun1,988,420,101,200,000,0001,988,420,101,200,000,000
Mercury330,107,382,800330,107,382,800
Venus4,867,372,861,0004,867,372,861,000
Moon73,458,060,000 
Jupiter1,898,162,242,600,0001,898,162,242,600,000
Uranus86,811,899,200,00086,811,899,200,000
Neptune102,417,257,800,000102,417,257,800,000
Total Mass102,417,257,800,000
99.97%
1,990,512,690,079,840,000
99.97%
Dispersed
Moon 73,458,060,000
Mars641,694,973,400641,694,973,400
Saturn568,417,257,800,000568,417,257,800,000
Total Mass568,974,163,573,400
0.03%
569,047,621,633,400
0.03%

With all that mass on one side of the solar system might something happen?

  • Might the plane of the solar system tilt and the stars not appear in their normal places?
  • Might we have higher than normal tides?
  • Might we not be here to see if the world ends on 21Dec12?


And at noon on 16Feb10 Venus and Jupiter will be conjuncted (the actual time of conjunction in R.A. is ~1630 EDT when the two planets will be separated by 34’ 18”, a little more than a Moon diameter) and ~9° east of the Sun so the conjunction might be visible all day with optics if one was to be careful. Venus and Jupiter rise that morning after sunrise and set within five minutes of sunset so there will be no opportunity to see the conjunction in a dark sky.

Cartes du Ciel graphic